そだダ獶程虏痷だ计㎝
そだダ琌9┮Τ獶程虏痷だ计Τ $\frac{1}{9}$$\frac{2}{9}$$\frac{3}{9}$$\frac{4}{9}$$\frac{5}{9}$$\frac{6}{9}$$\frac{7}{9}$$\frac{8}{9}$
芠诡衡Α
$\frac{1}{3}+\frac{2}{3}$=1
$\frac{1}{4}+\frac{2}{4}+\frac{3}{4}$=$\frac{3}{2}$
$\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}$=2
$\frac{1}{6}+\frac{2}{6}+\frac{3}{6}+\frac{4}{6}+\frac{5}{6}$=$\frac{5}{2}$
$\frac{1}{7}+\frac{2}{7}+\frac{3}{7}+\frac{4}{7}+\frac{5}{7}+\frac{6}{7}$=3
$\frac{1}{8}+\frac{2}{8}+\frac{3}{8}+\frac{4}{8}+\frac{5}{8}+\frac{6}{8}+\frac{7}{8}$=$\frac{7}{2}$
祇瞷狦そだダ琌计玥┮Τ獶程虏痷だ计㎝琌俱计;狦そだダ琌案计玥┮Τ獶程虏痷だ计㎝ぃ琌俱计
そだダ琌n┮Τ獶程虏痷だ计$\frac{1}{n}$$\frac{2}{n}$$\frac{3}{n}$.......$\frac{n-1}{n}$n-1だ计ㄤ㎝琌$\large\frac{\frac{(n-1)[1+(n-1)]}{2}}{n}$=$\frac{n-1}{2}$狦n琌计玥㎝琌俱计ㄒそだダ琌101┮Τ獶程虏痷だ计㎝琌50
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